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  1. #include <stdio.h>
  2.  
  3. // 正の奇数を引数とし，n以下の正の奇数の和を求める関数
  4. int rec(int n) {
  5.     if (n == 1) {
  6.         return 1;
  7.     } else {
  8.         return n + rec(n - 2);
  9.     }
  10. }
  11.  
  12. int main(void) {
  13.     int n = 11;
  14.     printf("%d以下の正の奇数の和は%d\n", n, rec(n));
  15.     return 0;
  16. }
Success #stdin #stdout 0.01s 5288KB
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11以下の正の奇数の和は36
https://ideone.com/N72wsY
language:
C (gcc 8.3)
created:
18 hours ago
visibility:
public

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