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  1. #include <stdio.h>
  2.  
  3. // 再帰を用いて1からnまでの二乗和 (1^2+2^2+...+n^2) の値を計算する
  4. int rec(int n) {
  5.     if (n == 1) {
  6.         return 1;
  7.     } else {
  8.         return rec(n - 1) + n * n;
  9.     }
  10. }
  11. int main(void) {
  12.     int n = 4;
  13.     printf("1から%dまでの二乗和の値は%d\n", n, rec(n));
  14.     return 0;
  15. }
  16.  
Success #stdin #stdout 0.01s 5288KB
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1から4までの二乗和の値は30
https://ideone.com/jQC3LL
language:
C (gcc 8.3)
created:
18 hours ago
visibility:
public

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